CSIR NET Answer Key 2025 and Response Sheet, Soon @exams.nta.ac.in

 Formfees 28/02/2025

The answer key for the Joint CSIR-UGC NET December 2024 will be released on the official website of the NTA Exams in the first week of March 2025. Candidates who have participated in the exam held from 28 to 28 February to 02 March 2025 should know that it will be released under the candidate’s login.

The National Testing Agency will release the answer key and response sheet simultaneously for the Joint CSIR-UGC NET December 2024 for Chemical Sciences; Earth, Atmospheric, Ocean, and Planetary Sciences; Life Sciences; Mathematical Sciences; and Physical Sciences. After its release, a direct link to access it will be also made available below for convenience.

If you are among those aspirants who have participated in the Joint CSIR-UGC NET December 2024 for any subject, you should know that the answer key and response sheet will be accessible using login credentials. It is highly recommended to all the candidates to be ready with login credentials to access this document shortly after its release on the web-portal.

Country India
Exam Name Joint CSIR-UGC NET December 2024
Conducting Body National Testing Agency (NTA)
Exam Date 28 February to 02 March 2025
Answer Key & Response Sheet Release Date First week of March 2025
Objection Window Date 3 to 5 days after answer key release
Answer Key & Response Sheet Release Status  To be released 
Answer Key & Response Sheet Download Link  Available Soon 
Official Website https://exams.nta.ac.in/

By accessing the answer key for the Joint CSIR-UGC National Eligibility Test December 2024 aspirants will be able to check the correct responses for all MCQs asked in the exam. By getting the digital copy of answer key and response sheet for the Joint CSIR-UGC NET December 2024, aspirants will be able to evaluate their tentative score.

How to download the Joint CSIR-UGC NET December 2024 Answer Key & Response Sheet?

In order to answer key and response sheets for the Joint CSIR-UGC NET December 2024, you are required to go through the step-by-step instructions available below.

  • Go to the official website of the NTA Exams, which is accessible at https://exams.nta.ac.in/.
  • Lookout for an option that reads ‘Joint CSIR-UGC NET December 2024,’ and click on it to get redirected to the next webpage.
  • Now, you will see an option that reads ‘Answer Key & Response Sheet,’ under the section of Candidate Activity, tap on it and go to the next page.
  • Lastly, you have to enter your Application Number and Password, and hit the Submit button to get the digital copy of these documents.

Raise Objection 

Candidates who have participated in the Joint CSIR-UGC NET December 2024 should know that after the release of the answer key, the window to raise objections against it will be available for 3 to 5 days. Individuals who will be unsatisfied with the answer key will be able to raise an objection by providing required proof and paying the required amount.

To raise an objection against the Joint CSIR-UGC NET December 2024 Answer Key, a candidate is required to pay ₹200/- using the debit card, credit card, NET banking or any other provided payment gateway. The exact date for availability of the objection window will be available on the notice that will be released with the answer key.

CSIR NET Answer Key 2025

Score Evaluation 

To evaluate the score for the Joint CSIR-UGC NET December 2024 using the answer key and response, you are required to go through the step-by-step instructions below:

  • Download the answer key and response sheet for the Joint CSIR-UGC NET December 2024 from the official website of the NTA Exams.
  • Compare the answer key and response sheet and find out the number of correct and incorrect responses. 
  • As each question carries weightage of 2 marks and 4 marks in Part A & B and Part C, respectively, and there is a provision of negative marking of ¼ of question weightage, you are required to use the formula available below.

Tentative Score for the Joint CSIR-UGC NET December 2025: Number of Correct Responses in Part A & B × 2 + Number of Correct Responses in Part C × 4 – Number of Correct Responses in Part A & B × 0.5 + Number of Correct Responses in Part C × 1.

The post CSIR NET Answer Key 2025 and Response Sheet, Soon @exams.nta.ac.in appeared first on DNK News.

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